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2145144045101 is a prime number
BaseRepresentation
bin11111001101110100100…
…011000111111000101101
321121001222202222022000012
4133031310203013320231
5240121223333420401
64321244321343005
7310660445350301
oct37156443077055
97531882868005
102145144045101
11757828987172
122a78b0497a65
13127394a7a525
1475b7b357d01
153ac0060a8bb
hex1f3748c7e2d

2145144045101 has 2 divisors, whose sum is σ = 2145144045102. Its totient is φ = 2145144045100.

The previous prime is 2145144045061. The next prime is 2145144045103. The reversal of 2145144045101 is 1015404415412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1610739184201 + 534404860900 = 1269149^2 + 731030^2 .

It is a cyclic number.

It is not a de Polignac number, because 2145144045101 - 222 = 2145139850797 is a prime.

It is a super-2 number, since 2×21451440451012 (a number of 25 digits) contains 22 as substring.

Together with 2145144045103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2145144045103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072572022550 + 1072572022551.

It is an arithmetic number, because the mean of its divisors is an integer number (1072572022551).

Almost surely, 22145144045101 is an apocalyptic number.

It is an amenable number.

2145144045101 is a deficient number, since it is larger than the sum of its proper divisors (1).

2145144045101 is an equidigital number, since it uses as much as digits as its factorization.

2145144045101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12800, while the sum is 32.

The spelling of 2145144045101 in words is "two trillion, one hundred forty-five billion, one hundred forty-four million, forty-five thousand, one hundred one".