Base | Representation |
---|---|
bin | 11111010011010111110… |
… | …011010100001001111100 |
3 | 21121122101011001121022120 |
4 | 133103113303110021330 |
5 | 240220430133420330 |
6 | 4324111552242540 |
7 | 311261240011143 |
oct | 37232763241174 |
9 | 7548334047276 |
10 | 2151104201340 |
11 | 75a307273826 |
12 | 2a8a94540450 |
13 | 127b048058b3 |
14 | 76184b5475a |
15 | 3ae4d9c2c10 |
hex | 1f4d7cd427c |
2151104201340 has 24 divisors (see below), whose sum is σ = 6023091763920. Its totient is φ = 573627787008.
The previous prime is 2151104201293. The next prime is 2151104201357. The reversal of 2151104201340 is 431024011512.
It is a self number, because there is not a number n which added to its sum of digits gives 2151104201340.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17925868285 + ... + 17925868404.
It is an arithmetic number, because the mean of its divisors is an integer number (250962156830).
Almost surely, 22151104201340 is an apocalyptic number.
2151104201340 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2151104201340 is an abundant number, since it is smaller than the sum of its proper divisors (3871987562580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2151104201340 is a wasteful number, since it uses less digits than its factorization.
2151104201340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35851736701 (or 35851736699 counting only the distinct ones).
The product of its (nonzero) digits is 960, while the sum is 24.
Adding to 2151104201340 its reverse (431024011512), we get a palindrome (2582128212852).
The spelling of 2151104201340 in words is "two trillion, one hundred fifty-one billion, one hundred four million, two hundred one thousand, three hundred forty".
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