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2151412117 is a prime number
BaseRepresentation
bin1000000000111011…
…1111000110010101
312112221021001121021
42000032333012111
513401230141432
6553252121141
7104212462351
oct20016770625
95487231537
102151412117
11a04463848
125006061b1
1328394bc2a
14165a30461
15c8d20697
hex803bf195

2151412117 has 2 divisors, whose sum is σ = 2151412118. Its totient is φ = 2151412116.

The previous prime is 2151412097. The next prime is 2151412171. The reversal of 2151412117 is 7112141512.

It is a happy number.

Together with next prime (2151412171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2127146641 + 24265476 = 46121^2 + 4926^2 .

It is a cyclic number.

It is not a de Polignac number, because 2151412117 - 211 = 2151410069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2151412091 and 2151412100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2151412217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075706058 + 1075706059.

It is an arithmetic number, because the mean of its divisors is an integer number (1075706059).

Almost surely, 22151412117 is an apocalyptic number.

It is an amenable number.

2151412117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2151412117 is an equidigital number, since it uses as much as digits as its factorization.

2151412117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 560, while the sum is 25.

The square root of 2151412117 is about 46383.3172272100. The cubic root of 2151412117 is about 1290.9453873594.

Adding to 2151412117 its reverse (7112141512), we get a palindrome (9263553629).

The spelling of 2151412117 in words is "two billion, one hundred fifty-one million, four hundred twelve thousand, one hundred seventeen".