Base | Representation |
---|---|
bin | 1100100010100101000… |
… | …0010011010101010111 |
3 | 202121002102022120021112 |
4 | 3020221100103111113 |
5 | 12012210232113101 |
6 | 242545541405235 |
7 | 21364550033045 |
oct | 3105120232527 |
9 | 677072276245 |
10 | 215440504151 |
11 | 83405603534 |
12 | 3590670981b |
13 | 174151bb972 |
14 | a5daa11395 |
15 | 590dc9d6bb |
hex | 3229413557 |
215440504151 has 2 divisors, whose sum is σ = 215440504152. Its totient is φ = 215440504150.
The previous prime is 215440504117. The next prime is 215440504177. The reversal of 215440504151 is 151405044512.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-215440504151 is a prime.
It is a super-2 number, since 2×2154405041512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (215440503151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107720252075 + 107720252076.
It is an arithmetic number, because the mean of its divisors is an integer number (107720252076).
Almost surely, 2215440504151 is an apocalyptic number.
215440504151 is a deficient number, since it is larger than the sum of its proper divisors (1).
215440504151 is an equidigital number, since it uses as much as digits as its factorization.
215440504151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16000, while the sum is 32.
Adding to 215440504151 its reverse (151405044512), we get a palindrome (366845548663).
The spelling of 215440504151 in words is "two hundred fifteen billion, four hundred forty million, five hundred four thousand, one hundred fifty-one".
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