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2158112903 is a prime number
BaseRepresentation
bin1000000010100010…
…0011000010000111
312120101212111100112
42000220203002013
513404434103103
6554051503235
7104323441232
oct20050430207
95511774315
102158112903
11a08220191
125028b7b1b
13285156bab
14166896419
15c96e5cd8
hex80a23087

2158112903 has 2 divisors, whose sum is σ = 2158112904. Its totient is φ = 2158112902.

The previous prime is 2158112867. The next prime is 2158112969. The reversal of 2158112903 is 3092118512.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2158112903 - 224 = 2141335687 is a prime.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2158112903.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2158112993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1079056451 + 1079056452.

It is an arithmetic number, because the mean of its divisors is an integer number (1079056452).

Almost surely, 22158112903 is an apocalyptic number.

2158112903 is a deficient number, since it is larger than the sum of its proper divisors (1).

2158112903 is an equidigital number, since it uses as much as digits as its factorization.

2158112903 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 32.

The square root of 2158112903 is about 46455.4937870646. The cubic root of 2158112903 is about 1292.2842573708.

It can be divided in two parts, 215 and 8112903, that added together give a palindrome (8113118).

The spelling of 2158112903 in words is "two billion, one hundred fifty-eight million, one hundred twelve thousand, nine hundred three".