Base | Representation |
---|---|
bin | 110001010111101011000110… |
… | …110111000101011111010000 |
3 | 1001110210112100121002100200010 |
4 | 301113223012313011133100 |
5 | 211424434004412324102 |
6 | 2045444353430554520 |
7 | 63510130252313214 |
oct | 6127530667053720 |
9 | 1043715317070603 |
10 | 217131113011152 |
11 | 6320387377556a |
12 | 2042956a508a40 |
13 | 94204b73a2512 |
14 | 3b892b81bc944 |
15 | 1a1812a0ead6c |
hex | c57ac6dc57d0 |
217131113011152 has 80 divisors (see below), whose sum is σ = 564594209407872. Its totient is φ = 71903690956800.
The previous prime is 217131113011093. The next prime is 217131113011159. The reversal of 217131113011152 is 251110311131712.
It is a super-2 number, since 2×2171311130111522 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (217131113011159) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6916768 + ... + 21956864.
Almost surely, 2217131113011152 is an apocalyptic number.
It is an amenable number.
217131113011152 is an abundant number, since it is smaller than the sum of its proper divisors (347463096396720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
217131113011152 is a wasteful number, since it uses less digits than its factorization.
217131113011152 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15042076 (or 15042070 counting only the distinct ones).
The product of its (nonzero) digits is 1260, while the sum is 30.
Adding to 217131113011152 its reverse (251110311131712), we get a palindrome (468241424142864).
The spelling of 217131113011152 in words is "two hundred seventeen trillion, one hundred thirty-one billion, one hundred thirteen million, eleven thousand, one hundred fifty-two".
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