Base | Representation |
---|---|
bin | 100000001100001100101… |
… | …000000111011000000111 |
3 | 21211110212110001022212122 |
4 | 200030030220013120013 |
5 | 242220410210000012 |
6 | 4412122304440155 |
7 | 315551252520041 |
oct | 40141450073007 |
9 | 7743773038778 |
10 | 2212120000007 |
11 | 783178085415 |
12 | 2b888261905b |
13 | 1307a9841c88 |
14 | 790d24a8a91 |
15 | 3c8204c7e72 |
hex | 2030ca07607 |
2212120000007 has 2 divisors, whose sum is σ = 2212120000008. Its totient is φ = 2212120000006.
The previous prime is 2212119999983. The next prime is 2212120000031. The reversal of 2212120000007 is 7000000212122.
It is a balanced prime because it is at equal distance from previous prime (2212119999983) and next prime (2212120000031).
It is a cyclic number.
It is not a de Polignac number, because 2212120000007 - 216 = 2212119934471 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2212120000007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2212120000067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1106060000003 + 1106060000004.
It is an arithmetic number, because the mean of its divisors is an integer number (1106060000004).
Almost surely, 22212120000007 is an apocalyptic number.
2212120000007 is a deficient number, since it is larger than the sum of its proper divisors (1).
2212120000007 is an equidigital number, since it uses as much as digits as its factorization.
2212120000007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 17.
Adding to 2212120000007 its reverse (7000000212122), we get a palindrome (9212120212129).
The spelling of 2212120000007 in words is "two trillion, two hundred twelve billion, one hundred twenty million, seven", and thus it is an aban number.
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