Base | Representation |
---|---|
bin | 1010000100011100111100… |
… | …10010101100100010001101 |
3 | 2220101212111112011102200121 |
4 | 11002032132102230202031 |
5 | 10400243244300041023 |
6 | 115032241243424541 |
7 | 4443536303263216 |
oct | 502163622544215 |
9 | 86355445142617 |
10 | 22143212112013 |
11 | 7067979a68293 |
12 | 2597604b25151 |
13 | c48132a29895 |
14 | 567a46b9840d |
15 | 285ee0a76d5d |
hex | 14239e4ac88d |
22143212112013 has 2 divisors, whose sum is σ = 22143212112014. Its totient is φ = 22143212112012.
The previous prime is 22143212111957. The next prime is 22143212112041. The reversal of 22143212112013 is 31021121234122.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19539255424329 + 2603956687684 = 4420323^2 + 1613678^2 .
It is a cyclic number.
It is not a de Polignac number, because 22143212112013 - 237 = 22005773158541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22143212112083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11071606056006 + 11071606056007.
It is an arithmetic number, because the mean of its divisors is an integer number (11071606056007).
Almost surely, 222143212112013 is an apocalyptic number.
It is an amenable number.
22143212112013 is a deficient number, since it is larger than the sum of its proper divisors (1).
22143212112013 is an equidigital number, since it uses as much as digits as its factorization.
22143212112013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 22143212112013 its reverse (31021121234122), we get a palindrome (53164333346135).
The spelling of 22143212112013 in words is "twenty-two trillion, one hundred forty-three billion, two hundred twelve million, one hundred twelve thousand, thirteen".
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