Base | Representation |
---|---|
bin | 110010111011111111101010… |
… | …010010111011110001000000 |
3 | 1002101012121000111100202100221 |
4 | 302323333222102323301000 |
5 | 213330411431241232000 |
6 | 2112243420213152424 |
7 | 65121165364124614 |
oct | 6273775222736100 |
9 | 1071177014322327 |
10 | 224025130024000 |
11 | 65421584636a28 |
12 | 211616a292b714 |
13 | 980062c7cb216 |
14 | 3d46c34933344 |
15 | 1ad761b1d861a |
hex | cbbfea4bbc40 |
224025130024000 has 56 divisors (see below), whose sum is σ = 554798234524248. Its totient is φ = 89610052006400.
The previous prime is 224025130023979. The next prime is 224025130024039. The reversal of 224025130024000 is 420031520422.
It can be written as a sum of positive squares in 4 ways, for example, as 69186329180224 + 154838800843776 = 8317832^2 + 12443424^2 .
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14001562627 + ... + 14001578626.
Almost surely, 2224025130024000 is an apocalyptic number.
224025130024000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
224025130024000 is an abundant number, since it is smaller than the sum of its proper divisors (330773104500248).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
224025130024000 is an equidigital number, since it uses as much as digits as its factorization.
224025130024000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28003141280 (or 28003141260 counting only the distinct ones).
The product of its (nonzero) digits is 3840, while the sum is 25.
Adding to 224025130024000 its reverse (420031520422), we get a palindrome (224445161544422).
The spelling of 224025130024000 in words is "two hundred twenty-four trillion, twenty-five billion, one hundred thirty million, twenty-four thousand".
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