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230439914981 is a prime number
BaseRepresentation
bin1101011010011101001…
…0100000110111100101
3211000210202100120202222
43112213102200313211
512233420104234411
6253510155042125
722435341646553
oct3264722406745
9730722316688
10230439914981
1189802362931
12387b1a40345
131896588c7a3
14b220b20bd3
155eda9e84db
hex35a74a0de5

230439914981 has 2 divisors, whose sum is σ = 230439914982. Its totient is φ = 230439914980.

The previous prime is 230439914977. The next prime is 230439914983. The reversal of 230439914981 is 189419934032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 153769073956 + 76670841025 = 392134^2 + 276895^2 .

It is a cyclic number.

It is not a de Polignac number, because 230439914981 - 22 = 230439914977 is a prime.

It is a super-2 number, since 2×2304399149812 (a number of 24 digits) contains 22 as substring.

Together with 230439914983, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (230439914983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115219957490 + 115219957491.

It is an arithmetic number, because the mean of its divisors is an integer number (115219957491).

Almost surely, 2230439914981 is an apocalyptic number.

It is an amenable number.

230439914981 is a deficient number, since it is larger than the sum of its proper divisors (1).

230439914981 is an equidigital number, since it uses as much as digits as its factorization.

230439914981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1679616, while the sum is 53.

The spelling of 230439914981 in words is "two hundred thirty billion, four hundred thirty-nine million, nine hundred fourteen thousand, nine hundred eighty-one".