Base | Representation |
---|---|
bin | 1101011010011101101… |
… | …0100000110111100101 |
3 | 211000210220022010112021 |
4 | 3112213122200313211 |
5 | 12233421123342013 |
6 | 253510312023141 |
7 | 22435365532654 |
oct | 3264732406745 |
9 | 730726263467 |
10 | 230442012133 |
11 | 89803565513 |
12 | 387b2691ab1 |
13 | 189661451c8 |
14 | b22110919b |
15 | 5edacaea8d |
hex | 35a76a0de5 |
230442012133 has 2 divisors, whose sum is σ = 230442012134. Its totient is φ = 230442012132.
The previous prime is 230442012089. The next prime is 230442012161. The reversal of 230442012133 is 331210244032.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 196921162564 + 33520849569 = 443758^2 + 183087^2 .
It is a cyclic number.
It is not a de Polignac number, because 230442012133 - 221 = 230439914981 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 230442012098 and 230442012107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (230442018133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115221006066 + 115221006067.
It is an arithmetic number, because the mean of its divisors is an integer number (115221006067).
Almost surely, 2230442012133 is an apocalyptic number.
It is an amenable number.
230442012133 is a deficient number, since it is larger than the sum of its proper divisors (1).
230442012133 is an equidigital number, since it uses as much as digits as its factorization.
230442012133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 230442012133 its reverse (331210244032), we get a palindrome (561652256165).
The spelling of 230442012133 in words is "two hundred thirty billion, four hundred forty-two million, twelve thousand, one hundred thirty-three".
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