23110444013141 has 2 divisors, whose sum is σ = 23110444013142. Its totient is φ = 23110444013140.

The previous prime is 23110444013117. The next prime is 23110444013143. The reversal of 23110444013141 is 14131044401132.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21467663489041 + 1642780524100 = 4633321^2 + 1281710^2 .

It is a cyclic number.

It is not a de Polignac number, because 23110444013141 - 2¹⁸ = 23110443750997 is a prime.

Together with 23110444013143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23110444013143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11555222006570 + 11555222006571.

It is an arithmetic number, because the mean of its divisors is an integer number (11555222006571).

Almost surely, 2^{23110444013141} is an apocalyptic number.

It is an amenable number.

23110444013141 is a deficient number, since it is larger than the sum of its proper divisors (1).

23110444013141 is an equidigital number, since it uses as much as digits as its factorization.

23110444013141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 23110444013141 its reverse (14131044401132), we get a palindrome (37241488414273).

The spelling of 23110444013141 in words is "twenty-three trillion, one hundred ten billion, four hundred forty-four million, thirteen thousand, one hundred forty-one".