Base | Representation |
---|---|
bin | 100001101011000110000… |
… | …000000110010101111101 |
3 | 22012012212122012002121222 |
4 | 201223012000012111331 |
5 | 300403100131214442 |
6 | 4531013221403125 |
7 | 326116301120252 |
oct | 41530600062575 |
9 | 8165778162558 |
10 | 2314014319997 |
11 | 812405837126 |
12 | 31457a8694a5 |
13 | 13a297946b03 |
14 | 7dddad55429 |
15 | 402d5b9c8d2 |
hex | 21ac600657d |
2314014319997 has 2 divisors, whose sum is σ = 2314014319998. Its totient is φ = 2314014319996.
The previous prime is 2314014319993. The next prime is 2314014319999. The reversal of 2314014319997 is 7999134104132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1707880445881 + 606133874116 = 1306859^2 + 778546^2 .
It is a cyclic number.
It is not a de Polignac number, because 2314014319997 - 22 = 2314014319993 is a prime.
Together with 2314014319999, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2314014319993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157007159998 + 1157007159999.
It is an arithmetic number, because the mean of its divisors is an integer number (1157007159999).
Almost surely, 22314014319997 is an apocalyptic number.
It is an amenable number.
2314014319997 is a deficient number, since it is larger than the sum of its proper divisors (1).
2314014319997 is an equidigital number, since it uses as much as digits as its factorization.
2314014319997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1469664, while the sum is 53.
The spelling of 2314014319997 in words is "two trillion, three hundred fourteen billion, fourteen million, three hundred nineteen thousand, nine hundred ninety-seven".
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