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2314014319997 is a prime number
BaseRepresentation
bin100001101011000110000…
…000000110010101111101
322012012212122012002121222
4201223012000012111331
5300403100131214442
64531013221403125
7326116301120252
oct41530600062575
98165778162558
102314014319997
11812405837126
1231457a8694a5
1313a297946b03
147dddad55429
15402d5b9c8d2
hex21ac600657d

2314014319997 has 2 divisors, whose sum is σ = 2314014319998. Its totient is φ = 2314014319996.

The previous prime is 2314014319993. The next prime is 2314014319999. The reversal of 2314014319997 is 7999134104132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1707880445881 + 606133874116 = 1306859^2 + 778546^2 .

It is a cyclic number.

It is not a de Polignac number, because 2314014319997 - 22 = 2314014319993 is a prime.

Together with 2314014319999, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2314014319993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157007159998 + 1157007159999.

It is an arithmetic number, because the mean of its divisors is an integer number (1157007159999).

Almost surely, 22314014319997 is an apocalyptic number.

It is an amenable number.

2314014319997 is a deficient number, since it is larger than the sum of its proper divisors (1).

2314014319997 is an equidigital number, since it uses as much as digits as its factorization.

2314014319997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1469664, while the sum is 53.

The spelling of 2314014319997 in words is "two trillion, three hundred fourteen billion, fourteen million, three hundred nineteen thousand, nine hundred ninety-seven".