Base | Representation |
---|---|
bin | 11011100110100… |
… | …01000000010111 |
3 | 121010200121000112 |
4 | 31303101000113 |
5 | 433233332212 |
6 | 34550433235 |
7 | 5511036626 |
oct | 1563210027 |
9 | 533617015 |
10 | 231542807 |
11 | 1097775a1 |
12 | 6566281b |
13 | 38c7c5a2 |
14 | 22a736bd |
15 | 154da422 |
hex | dcd1017 |
231542807 has 2 divisors, whose sum is σ = 231542808. Its totient is φ = 231542806.
The previous prime is 231542761. The next prime is 231542809. The reversal of 231542807 is 708245132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 231542807 - 28 = 231542551 is a prime.
It is a super-2 number, since 2×2315428072 = 107224142946878498, which contains 22 as substring.
Together with 231542809, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (231542809) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115771403 + 115771404.
It is an arithmetic number, because the mean of its divisors is an integer number (115771404).
Almost surely, 2231542807 is an apocalyptic number.
231542807 is a deficient number, since it is larger than the sum of its proper divisors (1).
231542807 is an equidigital number, since it uses as much as digits as its factorization.
231542807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 32.
The square root of 231542807 is about 15216.5307149823. The cubic root of 231542807 is about 614.0594670199.
Adding to 231542807 its reverse (708245132), we get a palindrome (939787939).
The spelling of 231542807 in words is "two hundred thirty-one million, five hundred forty-two thousand, eight hundred seven".
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