Base | Representation |
---|---|
bin | 1010100110100000011011… |
… | …01000001011111110010101 |
3 | 10001112201201201212211111121 |
4 | 11103100031220023332111 |
5 | 11023431130121340201 |
6 | 121325553130203541 |
7 | 4624221403615225 |
oct | 523201550137625 |
9 | 101481651784447 |
10 | 23313311121301 |
11 | 7479135395503 |
12 | 27463388835b1 |
13 | 1001588607076 |
14 | 5a852808c085 |
15 | 2a66756949a1 |
hex | 15340da0bf95 |
23313311121301 has 2 divisors, whose sum is σ = 23313311121302. Its totient is φ = 23313311121300.
The previous prime is 23313311121283. The next prime is 23313311121377. The reversal of 23313311121301 is 10312111331332.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 17776932712900 + 5536378408401 = 4216270^2 + 2352951^2 .
It is a cyclic number.
It is not a de Polignac number, because 23313311121301 - 221 = 23313309024149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23313311121391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11656655560650 + 11656655560651.
It is an arithmetic number, because the mean of its divisors is an integer number (11656655560651).
Almost surely, 223313311121301 is an apocalyptic number.
It is an amenable number.
23313311121301 is a deficient number, since it is larger than the sum of its proper divisors (1).
23313311121301 is an equidigital number, since it uses as much as digits as its factorization.
23313311121301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 23313311121301 its reverse (10312111331332), we get a palindrome (33625422452633).
The spelling of 23313311121301 in words is "twenty-three trillion, three hundred thirteen billion, three hundred eleven million, one hundred twenty-one thousand, three hundred one".
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