Base | Representation |
---|---|
bin | 100010000100100110011… |
… | …100001111000111010111 |
3 | 22021211120100011002221012 |
4 | 202010212130033013113 |
5 | 301330142420044341 |
6 | 4551343021042435 |
7 | 331106061402602 |
oct | 42044634170727 |
9 | 8254510132835 |
10 | 2341402112471 |
11 | 822a8a4a7a64 |
12 | 3199429b641b |
13 | 13ca40a83686 |
14 | 814784a1339 |
15 | 40d8a2d40eb |
hex | 2212670f1d7 |
2341402112471 has 2 divisors, whose sum is σ = 2341402112472. Its totient is φ = 2341402112470.
The previous prime is 2341402112447. The next prime is 2341402112473. The reversal of 2341402112471 is 1742112041432.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2341402112471 is a prime.
It is a super-3 number, since 3×23414021124713 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 2341402112473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2341402112473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170701056235 + 1170701056236.
It is an arithmetic number, because the mean of its divisors is an integer number (1170701056236).
Almost surely, 22341402112471 is an apocalyptic number.
2341402112471 is a deficient number, since it is larger than the sum of its proper divisors (1).
2341402112471 is an equidigital number, since it uses as much as digits as its factorization.
2341402112471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 32.
The spelling of 2341402112471 in words is "two trillion, three hundred forty-one billion, four hundred two million, one hundred twelve thousand, four hundred seventy-one".
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