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234143313167 is a prime number
BaseRepresentation
bin1101101000010000000…
…1110110110100001111
3211101100211221201000202
43122010001312310033
512314011142010132
6255321451444115
722626201216041
oct3320401666417
9741324851022
10234143313167
1190332883795
123946615663b
1319105c0306a
14b492907a91
156155bd1762
hex3684076d0f

234143313167 has 2 divisors, whose sum is σ = 234143313168. Its totient is φ = 234143313166.

The previous prime is 234143313119. The next prime is 234143313169. The reversal of 234143313167 is 761313341432.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 234143313167 - 28 = 234143312911 is a prime.

It is a super-2 number, since 2×2341433131672 (a number of 24 digits) contains 22 as substring.

Together with 234143313169, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 234143313167.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (234143313169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117071656583 + 117071656584.

It is an arithmetic number, because the mean of its divisors is an integer number (117071656584).

Almost surely, 2234143313167 is an apocalyptic number.

234143313167 is a deficient number, since it is larger than the sum of its proper divisors (1).

234143313167 is an equidigital number, since it uses as much as digits as its factorization.

234143313167 is an evil number, because the sum of its binary digits is even.

The product of its digits is 108864, while the sum is 38.

Adding to 234143313167 its reverse (761313341432), we get a palindrome (995456654599).

The spelling of 234143313167 in words is "two hundred thirty-four billion, one hundred forty-three million, three hundred thirteen thousand, one hundred sixty-seven".