241312305340031 has 2 divisors, whose sum is σ = 241312305340032. Its totient is φ = 241312305340030.

The previous prime is 241312305339977. The next prime is 241312305340033. The reversal of 241312305340031 is 130043503213142.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-241312305340031 is a prime.

It is a super-3 number, since 3×241312305340031³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 241312305340033, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 241312305340031.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (241312305340033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120656152670015 + 120656152670016.

It is an arithmetic number, because the mean of its divisors is an integer number (120656152670016).

Almost surely, 2^{241312305340031} is an apocalyptic number.

241312305340031 is a deficient number, since it is larger than the sum of its proper divisors (1).

241312305340031 is an equidigital number, since it uses as much as digits as its factorization.

241312305340031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 241312305340031 its reverse (130043503213142), we get a palindrome (371355808553173).

The spelling of 241312305340031 in words is "two hundred forty-one trillion, three hundred twelve billion, three hundred five million, three hundred forty thousand, thirty-one".