Base | Representation |
---|---|
bin | 110110111000111000010110… |
… | …101110011100000101101010 |
3 | 1011122201221010221202100210110 |
4 | 312320320112232130011222 |
5 | 223120122441124031102 |
6 | 2213231052343555150 |
7 | 101563546066122321 |
oct | 6670702656340552 |
9 | 1148657127670713 |
10 | 241403313111402 |
11 | 6aa1162a975302 |
12 | 230a96b515bab6 |
13 | a491308983650 |
14 | 4387da87390b8 |
15 | 1cd96c2c0d86c |
hex | db8e16b9c16a |
241403313111402 has 64 divisors (see below), whose sum is σ = 559555725141504. Its totient is φ = 68762608266240.
The previous prime is 241403313111383. The next prime is 241403313111421. The reversal of 241403313111402 is 204111313304142.
It is an interprime number because it is at equal distance from previous prime (241403313111383) and next prime (241403313111421).
It is a self number, because there is not a number n which added to its sum of digits gives 241403313111402.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1492163218 + ... + 1492324989.
It is an arithmetic number, because the mean of its divisors is an integer number (8743058205336).
Almost surely, 2241403313111402 is an apocalyptic number.
241403313111402 is an abundant number, since it is smaller than the sum of its proper divisors (318152412030102).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
241403313111402 is a wasteful number, since it uses less digits than its factorization.
241403313111402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2984488303.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 241403313111402 its reverse (204111313304142), we get a palindrome (445514626415544).
The spelling of 241403313111402 in words is "two hundred forty-one trillion, four hundred three billion, three hundred thirteen million, one hundred eleven thousand, four hundred two".
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