Base | Representation |
---|---|
bin | 1110001001101100101… |
… | …1000010101001101100 |
3 | 212020112120001110012200 |
4 | 3202123023002221230 |
5 | 12440403103002000 |
6 | 303404414101500 |
7 | 23364530630511 |
oct | 3423313025154 |
9 | 766476043180 |
10 | 243121531500 |
11 | 9411a848041 |
12 | 3b150aaa890 |
13 | 19c06cc7ca3 |
14 | baa508d308 |
15 | 64ce009500 |
hex | 389b2c2a6c |
243121531500 has 144 divisors (see below), whose sum is σ = 768630495360. Its totient is φ = 64691827200.
The previous prime is 243121531493. The next prime is 243121531517. The reversal of 243121531500 is 5135121342.
243121531500 is a `hidden beast` number, since 2 + 4 + 3 + 1 + 2 + 153 + 1 + 500 = 666.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2025156 + ... + 2141844.
Almost surely, 2243121531500 is an apocalyptic number.
243121531500 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 243121531500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (384315247680).
243121531500 is an abundant number, since it is smaller than the sum of its proper divisors (525508963860).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
243121531500 is a wasteful number, since it uses less digits than its factorization.
243121531500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117177 (or 117162 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 243121531500 its reverse (5135121342), we get a palindrome (248256652842).
The spelling of 243121531500 in words is "two hundred forty-three billion, one hundred twenty-one million, five hundred thirty-one thousand, five hundred".
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