Base | Representation |
---|---|
bin | 10110101001001110… |
… | …111011110100001001 |
3 | 2022202111021022021022 |
4 | 112221032323310021 |
5 | 344243402213001 |
6 | 15100355322225 |
7 | 1520345306561 |
oct | 265116736411 |
9 | 68674238238 |
10 | 24314101001 |
11 | a347748a53 |
12 | 48668b0375 |
13 | 23a63c3518 |
14 | 126923dda1 |
15 | 97488811b |
hex | 5a93bbd09 |
24314101001 has 2 divisors, whose sum is σ = 24314101002. Its totient is φ = 24314101000.
The previous prime is 24314100977. The next prime is 24314101003. The reversal of 24314101001 is 10010141342.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23110080400 + 1204020601 = 152020^2 + 34699^2 .
It is a cyclic number.
It is not a de Polignac number, because 24314101001 - 222 = 24309906697 is a prime.
Together with 24314101003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (24314101003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12157050500 + 12157050501.
It is an arithmetic number, because the mean of its divisors is an integer number (12157050501).
Almost surely, 224314101001 is an apocalyptic number.
It is an amenable number.
24314101001 is a deficient number, since it is larger than the sum of its proper divisors (1).
24314101001 is an equidigital number, since it uses as much as digits as its factorization.
24314101001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 24314101001 its reverse (10010141342), we get a palindrome (34324242343).
The spelling of 24314101001 in words is "twenty-four billion, three hundred fourteen million, one hundred one thousand, one".
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