2443313014132 has 12 divisors (see below), whose sum is σ = 4282936005600. Its totient is φ = 1219617012536.

The previous prime is 2443313014111. The next prime is 2443313014193. The reversal of 2443313014132 is 2314103133442.

2443313014132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 2443313014094 and 2443313014103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 509870938 + ... + 509875729.

It is an arithmetic number, because the mean of its divisors is an integer number (356911333800).

Almost surely, 2^{2443313014132} is an apocalyptic number.

It is an amenable number.

2443313014132 is a deficient number, since it is larger than the sum of its proper divisors (1839622991468).

2443313014132 is a wasteful number, since it uses less digits than its factorization.

2443313014132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1019747270 (or 1019747268 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 2443313014132 its reverse (2314103133442), we get a palindrome (4757416147574).

The spelling of 2443313014132 in words is "two trillion, four hundred forty-three billion, three hundred thirteen million, fourteen thousand, one hundred thirty-two".