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2443313014131 = 311137540436411
BaseRepresentation
bin100011100011100000110…
…011011110010101110011
322122120121200111022110110
4203203200303132111303
5310012401112423011
65110235325232403
7341344400644143
oct43434063362563
98576550438413
102443313014131
11862226554830
12335644702703
13149532442a52
1486385226923
1543852181ba6
hex238e0cde573

2443313014131 has 16 divisors (see below), whose sum is σ = 3579850793088. Its totient is φ = 1469987035200.

The previous prime is 2443313014111. The next prime is 2443313014193. The reversal of 2443313014131 is 1314103133442.

It is not a de Polignac number, because 2443313014131 - 210 = 2443313013107 is a prime.

It is a super-2 number, since 2×24433130141312 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2443313014111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 270213685 + ... + 270222726.

It is an arithmetic number, because the mean of its divisors is an integer number (223740674568).

Almost surely, 22443313014131 is an apocalyptic number.

2443313014131 is a deficient number, since it is larger than the sum of its proper divisors (1136537778957).

2443313014131 is a wasteful number, since it uses less digits than its factorization.

2443313014131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 540436562.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 2443313014131 its reverse (1314103133442), we get a palindrome (3757416147573).

The spelling of 2443313014131 in words is "two trillion, four hundred forty-three billion, three hundred thirteen million, fourteen thousand, one hundred thirty-one".

Divisors: 1 3 11 33 137 411 1507 4521 540436411 1621309233 5944800521 17834401563 74039788307 222119364921 814437671377 2443313014131