25113406181 has 2 divisors, whose sum is σ = 25113406182. Its totient is φ = 25113406180.

The previous prime is 25113406121. The next prime is 25113406183. The reversal of 25113406181 is 18160431152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24953257156 + 160149025 = 157966^2 + 12655^2 .

It is a cyclic number.

It is not a de Polignac number, because 25113406181 - 2¹⁴ = 25113389797 is a prime.

It is a super-2 number, since 2×25113406181² (a number of 22 digits) contains 22 as substring.

Together with 25113406183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25113406183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12556703090 + 12556703091.

It is an arithmetic number, because the mean of its divisors is an integer number (12556703091).

Almost surely, 2^25113406181 is an apocalyptic number.

It is an amenable number.

25113406181 is a deficient number, since it is larger than the sum of its proper divisors (1).

25113406181 is an equidigital number, since it uses as much as digits as its factorization.

25113406181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 32.

The spelling of 25113406181 in words is "twenty-five billion, one hundred thirteen million, four hundred six thousand, one hundred eighty-one".