Base | Representation |
---|---|
bin | 111001000111100110100100… |
… | …100100010010000010010110 |
3 | 1012221110112202201000220110000 |
4 | 321013212210210102002112 |
5 | 230411320314401301410 |
6 | 2250140442042312130 |
7 | 103625255215000236 |
oct | 7107464444220226 |
9 | 1187415681026400 |
10 | 251211103150230 |
11 | 73053037739643 |
12 | 2421248a1b8646 |
13 | aa2314a69b822 |
14 | 460697a1d7cc6 |
15 | 1e0989d551dc0 |
hex | e479a4912096 |
251211103150230 has 160 divisors (see below), whose sum is σ = 688242254436000. Its totient is φ = 65723893267968.
The previous prime is 251211103150199. The next prime is 251211103150289. The reversal of 251211103150230 is 32051301112152.
251211103150230 is a `hidden beast` number, since 2 + 5 + 1 + 2 + 1 + 110 + 315 + 0 + 230 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 251211103150194 and 251211103150203.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 2519898226 + ... + 2519997914.
It is an arithmetic number, because the mean of its divisors is an integer number (4301514090225).
Almost surely, 2251211103150230 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 251211103150230, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (344121127218000).
251211103150230 is an abundant number, since it is smaller than the sum of its proper divisors (437031151285770).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
251211103150230 is a wasteful number, since it uses less digits than its factorization.
251211103150230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158460 (or 158451 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 27.
Adding to 251211103150230 its reverse (32051301112152), we get a palindrome (283262404262382).
The spelling of 251211103150230 in words is "two hundred fifty-one trillion, two hundred eleven billion, one hundred three million, one hundred fifty thousand, two hundred thirty".
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