Search a number
-
+
2513397131221 is a prime number
BaseRepresentation
bin100100100100110010001…
…001001010011111010101
322220021111222010100021211
4210210302021022133111
5312134414131144341
65202345543141421
7346405216055134
oct44446211123725
98807458110254
102513397131221
11889a2017a259
12347143744871
1315302112c712
148991309791b
15455a4d5b181
hex2493224a7d5

2513397131221 has 2 divisors, whose sum is σ = 2513397131222. Its totient is φ = 2513397131220.

The previous prime is 2513397131209. The next prime is 2513397131237. The reversal of 2513397131221 is 1221317933152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1553291108721 + 960106022500 = 1246311^2 + 979850^2 .

It is a cyclic number.

It is not a de Polignac number, because 2513397131221 - 215 = 2513397098453 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2513397131261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256698565610 + 1256698565611.

It is an arithmetic number, because the mean of its divisors is an integer number (1256698565611).

Almost surely, 22513397131221 is an apocalyptic number.

It is an amenable number.

2513397131221 is a deficient number, since it is larger than the sum of its proper divisors (1).

2513397131221 is an equidigital number, since it uses as much as digits as its factorization.

2513397131221 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 68040, while the sum is 40.

The spelling of 2513397131221 in words is "two trillion, five hundred thirteen billion, three hundred ninety-seven million, one hundred thirty-one thousand, two hundred twenty-one".