Search a number
-
+
2513397131237 is a prime number
BaseRepresentation
bin100100100100110010001…
…001001010011111100101
322220021111222010100022102
4210210302021022133211
5312134414131144422
65202345543141445
7346405216055156
oct44446211123745
98807458110272
102513397131237
11889a2017a273
12347143744885
1315302112c725
148991309792d
15455a4d5b192
hex2493224a7e5

2513397131237 has 2 divisors, whose sum is σ = 2513397131238. Its totient is φ = 2513397131236.

The previous prime is 2513397131221. The next prime is 2513397131249. The reversal of 2513397131237 is 7321317933152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1991572935361 + 521824195876 = 1411231^2 + 722374^2 .

It is a cyclic number.

It is not a de Polignac number, because 2513397131237 - 24 = 2513397131221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2513397131191 and 2513397131200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2513397131737) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256698565618 + 1256698565619.

It is an arithmetic number, because the mean of its divisors is an integer number (1256698565619).

Almost surely, 22513397131237 is an apocalyptic number.

It is an amenable number.

2513397131237 is a deficient number, since it is larger than the sum of its proper divisors (1).

2513397131237 is an equidigital number, since it uses as much as digits as its factorization.

2513397131237 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 714420, while the sum is 47.

The spelling of 2513397131237 in words is "two trillion, five hundred thirteen billion, three hundred ninety-seven million, one hundred thirty-one thousand, two hundred thirty-seven".