Search a number
-
+
2513397131261 is a prime number
BaseRepresentation
bin100100100100110010001…
…001001010011111111101
322220021111222010100100022
4210210302021022133331
5312134414131200021
65202345543141525
7346405216055222
oct44446211123775
98807458110308
102513397131261
11889a2017a295
123471437448a5
1315302112c743
1489913097949
15455a4d5b1ab
hex2493224a7fd

2513397131261 has 2 divisors, whose sum is σ = 2513397131262. Its totient is φ = 2513397131260.

The previous prime is 2513397131249. The next prime is 2513397131263. The reversal of 2513397131261 is 1621317933152.

It is a happy number.

2513397131261 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1755574650361 + 757822480900 = 1324981^2 + 870530^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2513397131261 is a prime.

Together with 2513397131263, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2513397131263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256698565630 + 1256698565631.

It is an arithmetic number, because the mean of its divisors is an integer number (1256698565631).

Almost surely, 22513397131261 is an apocalyptic number.

It is an amenable number.

2513397131261 is a deficient number, since it is larger than the sum of its proper divisors (1).

2513397131261 is an equidigital number, since it uses as much as digits as its factorization.

2513397131261 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 204120, while the sum is 44.

The spelling of 2513397131261 in words is "two trillion, five hundred thirteen billion, three hundred ninety-seven million, one hundred thirty-one thousand, two hundred sixty-one".