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25303000030050 = 2352168686666867
BaseRepresentation
bin1011100000011010100000…
…10101000001101101100010
310022120221110120120222101010
411300031100111001231202
511304031021001430200
6125452012052521350
75221036633365621
oct560152025015542
9108527416528333
1025303000030050
118075a3a961876
122a07a83620256
1311170a789b9c2
146369593596b8
152dd2c8314150
hex170350541b62

25303000030050 has 24 divisors (see below), whose sum is σ = 62751440074896. Its totient is φ = 6747466674640.

The previous prime is 25303000030019. The next prime is 25303000030117. The reversal of 25303000030050 is 5003000030352.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 25303000029999 and 25303000030026.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 84343333284 + ... + 84343333583.

It is an arithmetic number, because the mean of its divisors is an integer number (2614643336454).

Almost surely, 225303000030050 is an apocalyptic number.

25303000030050 is an abundant number, since it is smaller than the sum of its proper divisors (37448440044846).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

25303000030050 is a wasteful number, since it uses less digits than its factorization.

25303000030050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 168686666882 (or 168686666877 counting only the distinct ones).

The product of its (nonzero) digits is 1350, while the sum is 21.

The spelling of 25303000030050 in words is "twenty-five trillion, three hundred three billion, thirty thousand, fifty".

Divisors: 1 2 3 5 6 10 15 25 30 50 75 150 168686666867 337373333734 506060000601 843433334335 1012120001202 1686866668670 2530300003005 4217166671675 5060600006010 8434333343350 12651500015025 25303000030050