2532544031 has 2 divisors, whose sum is σ = 2532544032. Its totient is φ = 2532544030.

The previous prime is 2532544013. The next prime is 2532544033. The reversal of 2532544031 is 1304452352.

It is a happy number.

Together with previous prime (2532544013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2532544031 is a prime.

It is a super-2 number, since 2×2532544031² = 12827558537907457922, which contains 22 as substring.

Together with 2532544033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2532543985 and 2532544003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2532544033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1266272015 + 1266272016.

It is an arithmetic number, because the mean of its divisors is an integer number (1266272016).

Almost surely, 2^2532544031 is an apocalyptic number.

2532544031 is a deficient number, since it is larger than the sum of its proper divisors (1).

2532544031 is an equidigital number, since it uses as much as digits as its factorization.

2532544031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 29.

The square root of 2532544031 is about 50324.3880340338. The cubic root of 2532544031 is about 1363.0726431223.

Adding to 2532544031 its reverse (1304452352), we get a palindrome (3836996383).

The spelling of 2532544031 in words is "two billion, five hundred thirty-two million, five hundred forty-four thousand, thirty-one".