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253266437 is a prime number
BaseRepresentation
bin11110001100010…
…00101000000101
3122122120021020102
433012020220011
51004314011222
641044213445
76163505054
oct1706105005
9578507212
10253266437
1111aa64906
127099a285
13406173c8
14258ca39b
151737bd92
hexf188a05

253266437 has 2 divisors, whose sum is σ = 253266438. Its totient is φ = 253266436.

The previous prime is 253266353. The next prime is 253266451. The reversal of 253266437 is 734662352.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 244891201 + 8375236 = 15649^2 + 2894^2 .

It is a cyclic number.

It is not a de Polignac number, because 253266437 - 212 = 253262341 is a prime.

It is a super-2 number, since 2×2532664372 = 128287776221349938, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 253266437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (253266457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126633218 + 126633219.

It is an arithmetic number, because the mean of its divisors is an integer number (126633219).

Almost surely, 2253266437 is an apocalyptic number.

It is an amenable number.

253266437 is a deficient number, since it is larger than the sum of its proper divisors (1).

253266437 is an equidigital number, since it uses as much as digits as its factorization.

253266437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 181440, while the sum is 38.

The square root of 253266437 is about 15914.3468920342. The cubic root of 253266437 is about 632.6922968766.

The spelling of 253266437 in words is "two hundred fifty-three million, two hundred sixty-six thousand, four hundred thirty-seven".