Base | Representation |
---|---|
bin | 111001100111011110011110… |
… | …010010000110110110101100 |
3 | 1020020012221101102101111210022 |
4 | 321213132132102012312230 |
5 | 231203212112321343000 |
6 | 2254535002122501312 |
7 | 104242435454622365 |
oct | 7147363622066654 |
9 | 1206187342344708 |
10 | 253401431043500 |
11 | 73817a41731693 |
12 | 24506a8a664838 |
13 | ab5186347a78c |
14 | 46809a239ab6c |
15 | 1e468457b4585 |
hex | e6779e486dac |
253401431043500 has 96 divisors (see below), whose sum is σ = 569681006294400. Its totient is φ = 98396444908800.
The previous prime is 253401431043367. The next prime is 253401431043521. The reversal of 253401431043500 is 5340134104352.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7479155 + ... + 23722154.
It is an arithmetic number, because the mean of its divisors is an integer number (5934177148900).
Almost surely, 2253401431043500 is an apocalyptic number.
253401431043500 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
253401431043500 is an abundant number, since it is smaller than the sum of its proper divisors (316279575250900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
253401431043500 is a wasteful number, since it uses less digits than its factorization.
253401431043500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31201804 (or 31201792 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 253401431043500 its reverse (5340134104352), we get a palindrome (258741565147852).
The spelling of 253401431043500 in words is "two hundred fifty-three trillion, four hundred one billion, four hundred thirty-one million, forty-three thousand, five hundred".
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