Base | Representation |
---|---|
bin | 100100111000010000110… |
… | …010010111110010100100 |
3 | 22222021111120210021110120 |
4 | 210320100302113302210 |
5 | 313010232430012430 |
6 | 5220125204521540 |
7 | 351045423333051 |
oct | 44702062276244 |
9 | 8867446707416 |
10 | 2534312344740 |
11 | 897883281790 |
12 | 34b2000b02b0 |
13 | 154ca52c95c7 |
14 | 8a938b3a028 |
15 | 45dcb10b610 |
hex | 24e10c97ca4 |
2534312344740 has 48 divisors (see below), whose sum is σ = 7741172255040. Its totient is φ = 614378750080.
The previous prime is 2534312344643. The next prime is 2534312344741. The reversal of 2534312344740 is 474432134352.
It is a junction number, because it is equal to n+sod(n) for n = 2534312344692 and 2534312344701.
It is not an unprimeable number, because it can be changed into a prime (2534312344741) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1919932935 + ... + 1919934254.
It is an arithmetic number, because the mean of its divisors is an integer number (161274421980).
Almost surely, 22534312344740 is an apocalyptic number.
2534312344740 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2534312344740 is an abundant number, since it is smaller than the sum of its proper divisors (5206859910300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2534312344740 is a wasteful number, since it uses less digits than its factorization.
2534312344740 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3839867212 (or 3839867210 counting only the distinct ones).
The product of its (nonzero) digits is 967680, while the sum is 42.
The spelling of 2534312344740 in words is "two trillion, five hundred thirty-four billion, three hundred twelve million, three hundred forty-four thousand, seven hundred forty".
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