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2540127423013 is a prime number
BaseRepresentation
bin100100111101101011011…
…001001000101000100101
322222211111211212212012221
4210331223121020220211
5313104140110014023
65222530214112341
7351342503564035
oct44755331105045
98884454785187
102540127423013
1189a2977890a4
1235036364b6b1
131556c0c8a21b
148ad2b16d8c5
154611b8b785d
hex24f6b648a25

2540127423013 has 2 divisors, whose sum is σ = 2540127423014. Its totient is φ = 2540127423012.

The previous prime is 2540127422983. The next prime is 2540127423047. The reversal of 2540127423013 is 3103247210452.

It is an a-pointer prime, because the next prime (2540127423047) can be obtained adding 2540127423013 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2102668203364 + 437459219649 = 1450058^2 + 661407^2 .

It is a cyclic number.

It is not a de Polignac number, because 2540127423013 - 229 = 2539590552101 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2540127423013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2540127423073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1270063711506 + 1270063711507.

It is an arithmetic number, because the mean of its divisors is an integer number (1270063711507).

Almost surely, 22540127423013 is an apocalyptic number.

It is an amenable number.

2540127423013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2540127423013 is an equidigital number, since it uses as much as digits as its factorization.

2540127423013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 34.

The spelling of 2540127423013 in words is "two trillion, five hundred forty billion, one hundred twenty-seven million, four hundred twenty-three thousand, thirteen".