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2550601365239 is a prime number
BaseRepresentation
bin100101000111011011101…
…100000011011011110111
3100000211112210110020212002
4211013123230003123313
5313242112422141424
65231421411045515
7352163164613534
oct45073354033367
910024483406762
102550601365239
118a3781a819a4
123523a72a089b
1315669cc07c85
148b642223d8b
1546531192cae
hex251dbb036f7

2550601365239 has 2 divisors, whose sum is σ = 2550601365240. Its totient is φ = 2550601365238.

The previous prime is 2550601365209. The next prime is 2550601365269. The reversal of 2550601365239 is 9325631060552.

It is a balanced prime because it is at equal distance from previous prime (2550601365209) and next prime (2550601365269).

It is a cyclic number.

It is not a de Polignac number, because 2550601365239 - 224 = 2550584588023 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2550601365193 and 2550601365202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2550601365209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275300682619 + 1275300682620.

It is an arithmetic number, because the mean of its divisors is an integer number (1275300682620).

Almost surely, 22550601365239 is an apocalyptic number.

2550601365239 is a deficient number, since it is larger than the sum of its proper divisors (1).

2550601365239 is an equidigital number, since it uses as much as digits as its factorization.

2550601365239 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458000, while the sum is 47.

The spelling of 2550601365239 in words is "two trillion, five hundred fifty billion, six hundred one million, three hundred sixty-five thousand, two hundred thirty-nine".