255122140211131 has 2 divisors, whose sum is σ = 255122140211132. Its totient is φ = 255122140211130.

The previous prime is 255122140211129. The next prime is 255122140211173. The reversal of 255122140211131 is 131112041221552.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 255122140211131 - 2¹ = 255122140211129 is a prime.

It is a super-2 number, since 2×255122140211131² (a number of 30 digits) contains 22 as substring.

Together with 255122140211129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 255122140211093 and 255122140211102.

It is not a weakly prime, because it can be changed into another prime (255122140211431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127561070105565 + 127561070105566.

It is an arithmetic number, because the mean of its divisors is an integer number (127561070105566).

Almost surely, 2^{255122140211131} is an apocalyptic number.

255122140211131 is a deficient number, since it is larger than the sum of its proper divisors (1).

255122140211131 is an equidigital number, since it uses as much as digits as its factorization.

255122140211131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 255122140211131 its reverse (131112041221552), we get a palindrome (386234181432683).

The spelling of 255122140211131 in words is "two hundred fifty-five trillion, one hundred twenty-two billion, one hundred forty million, two hundred eleven thousand, one hundred thirty-one".