Base | Representation |
---|---|
bin | 111010000000100010000000… |
… | …010100111001011111001111 |
3 | 1020110022112121011220110020022 |
4 | 322000202000110321133033 |
5 | 231414414313322010044 |
6 | 2302333552420412355 |
7 | 104511020661326135 |
oct | 7200420024713717 |
9 | 1213275534813208 |
10 | 255123210344399 |
11 | 74321167211301 |
12 | 24744706b470bb |
13 | ac480280b1537 |
14 | 470005a439755 |
15 | 1e765181693ee |
hex | e808805397cf |
255123210344399 has 2 divisors, whose sum is σ = 255123210344400. Its totient is φ = 255123210344398.
The previous prime is 255123210344297. The next prime is 255123210344501. The reversal of 255123210344399 is 993443012321552.
It is a balanced prime because it is at equal distance from previous prime (255123210344297) and next prime (255123210344501).
It is a cyclic number.
It is not a de Polignac number, because 255123210344399 - 216 = 255123210278863 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 255123210344399.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255123210344999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127561605172199 + 127561605172200.
It is an arithmetic number, because the mean of its divisors is an integer number (127561605172200).
Almost surely, 2255123210344399 is an apocalyptic number.
255123210344399 is a deficient number, since it is larger than the sum of its proper divisors (1).
255123210344399 is an equidigital number, since it uses as much as digits as its factorization.
255123210344399 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6998400, while the sum is 53.
The spelling of 255123210344399 in words is "two hundred fifty-five trillion, one hundred twenty-three billion, two hundred ten million, three hundred forty-four thousand, three hundred ninety-nine".
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