Base | Representation |
---|---|
bin | 111010000010010010100111… |
… | …010010111110000000100111 |
3 | 1020110202002200210211200022102 |
4 | 322002102213102332000213 |
5 | 231423404431021444333 |
6 | 2302505310443322315 |
7 | 104522531214044225 |
oct | 7202224722760047 |
9 | 1213662623750272 |
10 | 255244123234343 |
11 | 74368474402121 |
12 | 2476403052039b |
13 | ac56557456369 |
14 | 4705c4aad5b15 |
15 | 1e79743345ae8 |
hex | e824a74be027 |
255244123234343 has 2 divisors, whose sum is σ = 255244123234344. Its totient is φ = 255244123234342.
The previous prime is 255244123234241. The next prime is 255244123234357. The reversal of 255244123234343 is 343432321442552.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 255244123234343 - 216 = 255244123168807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255244123234843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127622061617171 + 127622061617172.
It is an arithmetic number, because the mean of its divisors is an integer number (127622061617172).
Almost surely, 2255244123234343 is an apocalyptic number.
255244123234343 is a deficient number, since it is larger than the sum of its proper divisors (1).
255244123234343 is an equidigital number, since it uses as much as digits as its factorization.
255244123234343 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8294400, while the sum is 47.
Adding to 255244123234343 its reverse (343432321442552), we get a palindrome (598676444676895).
The spelling of 255244123234343 in words is "two hundred fifty-five trillion, two hundred forty-four billion, one hundred twenty-three million, two hundred thirty-four thousand, three hundred forty-three".
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