Base | Representation |
---|---|
bin | 1001100001011111… |
… | …1001110111000101 |
3 | 20121011022201211211 |
4 | 2120113321313011 |
5 | 20213414400031 |
6 | 1101400331421 |
7 | 120231032245 |
oct | 23027716705 |
9 | 6534281754 |
10 | 2556403141 |
11 | 10a2028576 |
12 | 5b4173b71 |
13 | 31981a1a6 |
14 | 1a3733b25 |
15 | ee66cbb1 |
hex | 985f9dc5 |
2556403141 has 2 divisors, whose sum is σ = 2556403142. Its totient is φ = 2556403140.
The previous prime is 2556403139. The next prime is 2556403147. The reversal of 2556403141 is 1413046552.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2376172516 + 180230625 = 48746^2 + 13425^2 .
It is a cyclic number.
It is not a de Polignac number, because 2556403141 - 21 = 2556403139 is a prime.
Together with 2556403139, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2556403147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278201570 + 1278201571.
It is an arithmetic number, because the mean of its divisors is an integer number (1278201571).
Almost surely, 22556403141 is an apocalyptic number.
It is an amenable number.
2556403141 is a deficient number, since it is larger than the sum of its proper divisors (1).
2556403141 is an equidigital number, since it uses as much as digits as its factorization.
2556403141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
The square root of 2556403141 is about 50560.8854847302. The cubic root of 2556403141 is about 1367.3397755523.
Adding to 2556403141 its reverse (1413046552), we get a palindrome (3969449693).
The spelling of 2556403141 in words is "two billion, five hundred fifty-six million, four hundred three thousand, one hundred forty-one".
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