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255713051171 is a prime number
BaseRepresentation
bin1110111000100110101…
…1111000001000100011
3220110001002012221000002
43232021223320020203
513142200020114141
6313250054050215
724321544033424
oct3561153701043
9813032187002
10255713051171
11994a1395146
124168594996b
131b162879446
14c53b48764b
1569b966ee9b
hex3b89af8223

255713051171 has 2 divisors, whose sum is σ = 255713051172. Its totient is φ = 255713051170.

The previous prime is 255713051161. The next prime is 255713051173. The reversal of 255713051171 is 171150317552.

It is a happy number.

255713051171 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255713051171 is a prime.

It is a super-3 number, since 3×2557130511713 (a number of 35 digits) contains 333 as substring.

Together with 255713051173, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (255713051173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127856525585 + 127856525586.

It is an arithmetic number, because the mean of its divisors is an integer number (127856525586).

Almost surely, 2255713051171 is an apocalyptic number.

255713051171 is a deficient number, since it is larger than the sum of its proper divisors (1).

255713051171 is an equidigital number, since it uses as much as digits as its factorization.

255713051171 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36750, while the sum is 38.

The spelling of 255713051171 in words is "two hundred fifty-five billion, seven hundred thirteen million, fifty-one thousand, one hundred seventy-one".