2560111460741 has 2 divisors, whose sum is σ = 2560111460742. Its totient is φ = 2560111460740.

The previous prime is 2560111460737. The next prime is 2560111460743. The reversal of 2560111460741 is 1470641110652.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2557907627716 + 2203833025 = 1599346^2 + 46945^2 .

It is a cyclic number.

It is not a de Polignac number, because 2560111460741 - 2² = 2560111460737 is a prime.

Together with 2560111460743, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2560111460695 and 2560111460704.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2560111460743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280055730370 + 1280055730371.

It is an arithmetic number, because the mean of its divisors is an integer number (1280055730371).

Almost surely, 2^{2560111460741} is an apocalyptic number.

It is an amenable number.

2560111460741 is a deficient number, since it is larger than the sum of its proper divisors (1).

2560111460741 is an equidigital number, since it uses as much as digits as its factorization.

2560111460741 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 38.

The spelling of 2560111460741 in words is "two trillion, five hundred sixty billion, one hundred eleven million, four hundred sixty thousand, seven hundred forty-one".