25614133 has 2 divisors, whose sum is σ = 25614134. Its totient is φ = 25614132.

The previous prime is 25614131. The next prime is 25614151. The reversal of 25614133 is 33141652.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14311089 + 11303044 = 3783^2 + 3362^2 .

It is a cyclic number.

It is not a de Polignac number, because 25614133 - 2¹ = 25614131 is a prime.

Together with 25614131, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 25614098 and 25614107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25614131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12807066 + 12807067.

It is an arithmetic number, because the mean of its divisors is an integer number (12807067).

Almost surely, 2^25614133 is an apocalyptic number.

It is an amenable number.

25614133 is a deficient number, since it is larger than the sum of its proper divisors (1).

25614133 is an equidigital number, since it uses as much as digits as its factorization.

25614133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2160, while the sum is 25.

The square root of 25614133 is about 5061.0407032546. The cubic root of 25614133 is about 294.7767457648.

Adding to 25614133 its reverse (33141652), we get a palindrome (58755785).

The spelling of 25614133 in words is "twenty-five million, six hundred fourteen thousand, one hundred thirty-three".