2561938470 has 160 divisors (see below), whose sum is σ = 8478727488. Its totient is φ = 540525312.

The previous prime is 2561938459. The next prime is 2561938481. The reversal of 2561938470 is 748391652.

2561938470 is a `hidden beast` number, since 2 + 561 + 9 + 3 + 84 + 7 + 0 = 666.

2561938470 is digitally balanced in base 10, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (2561938459) and next prime (2561938481).

It is a Harshad number since it is a multiple of its sum of digits (45).

2561938470 is strictly pandigital in base 10.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 56332 + ... + 91088.

It is a 2-persistent number, because it is pandigital, and so is 2⋅2561938470 = 5123876940, but 3⋅2561938470 = 7685815410 is not.

Almost surely, 2^2561938470 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2561938470, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4239363744).

2561938470 is an abundant number, since it is smaller than the sum of its proper divisors (5916789018).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2561938470 is a wasteful number, since it uses less digits than its factorization.

2561938470 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34796 (or 34787 counting only the distinct ones).

The product of its (nonzero) digits is 362880, while the sum is 45.

The square root of 2561938470 is about 50615.5951264035. The cubic root of 2561938470 is about 1368.3259553381.

The spelling of 2561938470 in words is "two billion, five hundred sixty-one million, nine hundred thirty-eight thousand, four hundred seventy".