2580840212957 has 2 divisors, whose sum is σ = 2580840212958. Its totient is φ = 2580840212956.

The previous prime is 2580840212953. The next prime is 2580840212959. The reversal of 2580840212957 is 7592120480852.

2580840212957 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1858766849956 + 722073363001 = 1363366^2 + 849749^2 .

It is a cyclic number.

It is not a de Polignac number, because 2580840212957 - 2² = 2580840212953 is a prime.

It is a super-2 number, since 2×2580840212957² (a number of 26 digits) contains 22 as substring.

Together with 2580840212959, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2580840212899 and 2580840212908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2580840212953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1290420106478 + 1290420106479.

It is an arithmetic number, because the mean of its divisors is an integer number (1290420106479).

Almost surely, 2^{2580840212957} is an apocalyptic number.

It is an amenable number.

2580840212957 is a deficient number, since it is larger than the sum of its proper divisors (1).

2580840212957 is an equidigital number, since it uses as much as digits as its factorization.

2580840212957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3225600, while the sum is 53.

The spelling of 2580840212957 in words is "two trillion, five hundred eighty billion, eight hundred forty million, two hundred twelve thousand, nine hundred fifty-seven".