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2587131047 is a prime number
BaseRepresentation
bin1001101000110100…
…0111110010100111
320200022010212121102
42122031013302213
520244301143142
61104415110315
7121053152054
oct23215076247
96608125542
102587131047
111108405936
1260251239b
13322cb8597
141a785202b
151021dc532
hex9a347ca7

2587131047 has 2 divisors, whose sum is σ = 2587131048. Its totient is φ = 2587131046.

The previous prime is 2587131017. The next prime is 2587131049. The reversal of 2587131047 is 7401317852.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2587131047 - 212 = 2587126951 is a prime.

Together with 2587131049, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2587131047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2587131049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1293565523 + 1293565524.

It is an arithmetic number, because the mean of its divisors is an integer number (1293565524).

Almost surely, 22587131047 is an apocalyptic number.

2587131047 is a deficient number, since it is larger than the sum of its proper divisors (1).

2587131047 is an equidigital number, since it uses as much as digits as its factorization.

2587131047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 47040, while the sum is 38.

The square root of 2587131047 is about 50863.8481340136. The cubic root of 2587131047 is about 1372.7964346776.

Adding to 2587131047 its reverse (7401317852), we get a palindrome (9988448899).

The spelling of 2587131047 in words is "two billion, five hundred eighty-seven million, one hundred thirty-one thousand, forty-seven".