Base | Representation |
---|---|
bin | 111100000111111111110001… |
… | …111111101011000011111100 |
3 | 1021200021111000110002121000220 |
4 | 330013333301333223003330 |
5 | 234124424333221411330 |
6 | 2334222305450021340 |
7 | 106461414121562235 |
oct | 7407776177530374 |
9 | 1250244013077026 |
10 | 264432311513340 |
11 | 77290128127653 |
12 | 257a8906117850 |
13 | b471b244b2999 |
14 | 4942840c9208c |
15 | 2088758017710 |
hex | f07ff1feb0fc |
264432311513340 has 24 divisors (see below), whose sum is σ = 740410472237520. Its totient is φ = 70515283070208.
The previous prime is 264432311513311. The next prime is 264432311513417. The reversal of 264432311513340 is 43315113234462.
It is a junction number, because it is equal to n+sod(n) for n = 264432311513292 and 264432311513301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2203602595885 + ... + 2203602596004.
It is an arithmetic number, because the mean of its divisors is an integer number (30850436343230).
Almost surely, 2264432311513340 is an apocalyptic number.
264432311513340 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
264432311513340 is an abundant number, since it is smaller than the sum of its proper divisors (475978160724180).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
264432311513340 is a wasteful number, since it uses less digits than its factorization.
264432311513340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4407205191901 (or 4407205191899 counting only the distinct ones).
The product of its (nonzero) digits is 622080, while the sum is 42.
The spelling of 264432311513340 in words is "two hundred sixty-four trillion, four hundred thirty-two billion, three hundred eleven million, five hundred thirteen thousand, three hundred forty".
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