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268014055007 is a prime number
BaseRepresentation
bin1111100110011011100…
…0011110111001011111
3221121210100201122222202
43321212320132321133
513342343044230012
6323042435202115
725235431610366
oct3714670367137
9847710648882
10268014055007
11a3733a46416
1243b3944633b
131c3731a093a
14cd8705a7dd
156e8954bcc2
hex3e66e1ee5f

268014055007 has 2 divisors, whose sum is σ = 268014055008. Its totient is φ = 268014055006.

The previous prime is 268014054961. The next prime is 268014055009. The reversal of 268014055007 is 700550410862.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 268014055007 - 236 = 199294578271 is a prime.

Together with 268014055009, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (268014055009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 134007027503 + 134007027504.

It is an arithmetic number, because the mean of its divisors is an integer number (134007027504).

Almost surely, 2268014055007 is an apocalyptic number.

268014055007 is a deficient number, since it is larger than the sum of its proper divisors (1).

268014055007 is an equidigital number, since it uses as much as digits as its factorization.

268014055007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67200, while the sum is 38.

Adding to 268014055007 its reverse (700550410862), we get a palindrome (968564465869).

The spelling of 268014055007 in words is "two hundred sixty-eight billion, fourteen million, fifty-five thousand, seven".