Base | Representation |
---|---|
bin | 1111100110011011100… |
… | …0011110111001011111 |
3 | 221121210100201122222202 |
4 | 3321212320132321133 |
5 | 13342343044230012 |
6 | 323042435202115 |
7 | 25235431610366 |
oct | 3714670367137 |
9 | 847710648882 |
10 | 268014055007 |
11 | a3733a46416 |
12 | 43b3944633b |
13 | 1c3731a093a |
14 | cd8705a7dd |
15 | 6e8954bcc2 |
hex | 3e66e1ee5f |
268014055007 has 2 divisors, whose sum is σ = 268014055008. Its totient is φ = 268014055006.
The previous prime is 268014054961. The next prime is 268014055009. The reversal of 268014055007 is 700550410862.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 268014055007 - 236 = 199294578271 is a prime.
Together with 268014055009, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (268014055009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 134007027503 + 134007027504.
It is an arithmetic number, because the mean of its divisors is an integer number (134007027504).
Almost surely, 2268014055007 is an apocalyptic number.
268014055007 is a deficient number, since it is larger than the sum of its proper divisors (1).
268014055007 is an equidigital number, since it uses as much as digits as its factorization.
268014055007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67200, while the sum is 38.
Adding to 268014055007 its reverse (700550410862), we get a palindrome (968564465869).
The spelling of 268014055007 in words is "two hundred sixty-eight billion, fourteen million, fifty-five thousand, seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •