Base | Representation |
---|---|
bin | 1111100111110101000… |
… | …0101111001110110101 |
3 | 221122202112012212022122 |
4 | 3321331100233032311 |
5 | 13344130203341432 |
6 | 323144010405325 |
7 | 25250641132466 |
oct | 3717520571665 |
9 | 848675185278 |
10 | 268389512117 |
11 | a3906978951 |
12 | 44023130845 |
13 | 1c402bcb0cc |
14 | cdc0c72d6d |
15 | 6eac4b3612 |
hex | 3e7d42f3b5 |
268389512117 has 2 divisors, whose sum is σ = 268389512118. Its totient is φ = 268389512116.
The previous prime is 268389512093. The next prime is 268389512119. The reversal of 268389512117 is 711215983862.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 243442573201 + 24946938916 = 493399^2 + 157946^2 .
It is a cyclic number.
It is not a de Polignac number, because 268389512117 - 212 = 268389508021 is a prime.
Together with 268389512119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (268389512119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 134194756058 + 134194756059.
It is an arithmetic number, because the mean of its divisors is an integer number (134194756059).
Almost surely, 2268389512117 is an apocalyptic number.
It is an amenable number.
268389512117 is a deficient number, since it is larger than the sum of its proper divisors (1).
268389512117 is an equidigital number, since it uses as much as digits as its factorization.
268389512117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1451520, while the sum is 53.
The spelling of 268389512117 in words is "two hundred sixty-eight billion, three hundred eighty-nine million, five hundred twelve thousand, one hundred seventeen".
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