Base | Representation |
---|---|
bin | 11001001000001011… |
… | …010000110100011111 |
3 | 2120122022222101002122 |
4 | 121020023100310133 |
5 | 420224030401212 |
6 | 20221134213155 |
7 | 1643415205013 |
oct | 311013206437 |
9 | 76568871078 |
10 | 26980715807 |
11 | 10495a02141 |
12 | 528b9541bb |
13 | 270c9bb1c6 |
14 | 143d462543 |
15 | a7da26272 |
hex | 6482d0d1f |
26980715807 has 2 divisors, whose sum is σ = 26980715808. Its totient is φ = 26980715806.
The previous prime is 26980715803. The next prime is 26980715809. The reversal of 26980715807 is 70851708962.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 26980715807 - 22 = 26980715803 is a prime.
It is a super-2 number, since 2×269807158072 (a number of 22 digits) contains 22 as substring.
Together with 26980715809, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (26980715803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13490357903 + 13490357904.
It is an arithmetic number, because the mean of its divisors is an integer number (13490357904).
Almost surely, 226980715807 is an apocalyptic number.
26980715807 is a deficient number, since it is larger than the sum of its proper divisors (1).
26980715807 is an equidigital number, since it uses as much as digits as its factorization.
26980715807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1693440, while the sum is 53.
The spelling of 26980715807 in words is "twenty-six billion, nine hundred eighty million, seven hundred fifteen thousand, eight hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •