Base | Representation |
---|---|
bin | 101011110101010111000… |
… | …101000110111010000100 |
3 | 101122222002200212122122110 |
4 | 223311113011012322010 |
5 | 343323023124000200 |
6 | 10223444543501020 |
7 | 430424641210263 |
oct | 53652705067204 |
9 | 11588080778573 |
10 | 3012233031300 |
11 | a615320211a9 |
12 | 40795a8b7770 |
13 | 18b08b04566c |
14 | a5b158545da |
15 | 5354d695b50 |
hex | 2bd57146e84 |
3012233031300 has 72 divisors (see below), whose sum is σ = 8730875000736. Its totient is φ = 801835343360.
The previous prime is 3012233031251. The next prime is 3012233031307. The reversal of 3012233031300 is 31303322103.
3012233031300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (3012233031307) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8748309 + ... + 9086108.
It is an arithmetic number, because the mean of its divisors is an integer number (121262152788).
Almost surely, 23012233031300 is an apocalyptic number.
3012233031300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
3012233031300 is an abundant number, since it is smaller than the sum of its proper divisors (5718641969436).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3012233031300 is a wasteful number, since it uses less digits than its factorization.
3012233031300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17834997 (or 17834990 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 21.
Adding to 3012233031300 its reverse (31303322103), we get a palindrome (3043536353403).
The spelling of 3012233031300 in words is "three trillion, twelve billion, two hundred thirty-three million, thirty-one thousand, three hundred".
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